5.6 Extension to unequal masses

Let us consider now a baryon made of different quarks. We use the Jacobi coordinates of Eq. (3.52) and the corresponding reduced mass μ = 2m1m2(m1 + m2). If two quarks are identical, as in Λ, Σ or Ξ type of baryons, or almost identical, as s and u in Ξc+, they are assigned to labels 1 or 2. This helps to enforce the exact or approximate symmetry constraints. The hyperspherical treatment of

      1
H  =  -(pρ2+ p 2λ) + V (ρ, λ)
      μ
(5.25)

is then performed as for identical quarks. There are, however, more harmonics into the expansion, since some (if m1 = m2m3) or all (if m1m2m3) symmetry constrains are relaxed. This makes the use of potential harmonics more desirable.

In Ref. [58] is studied the case of harmonic forces, for which an exact solution is available. The results of the linear model V = 1 2 rijβ with β = 1, m 1 = m2 = 1, and m3 = mare shown in Table 5.3. Another example, more suited to double-charm baryons [7] is given in Table 5.3. The hyperscalar approximation is obviously rather poor for the wave function. However, the convergence remains satisfactory as Lmax increases.



Table 5.3: Convergence of the hyperspherical expansion for a power-law potential V = 1_ 2 rijβ with quark masses m 1 = m2 = 1 and m3 = m(for β = 0.1, the correlation coefficients are multiplied by 103)






β mLmax E0 δ(3)(r 12)δ(3)(r 13)






0 3.4671 0.0468 0.1006
2 3.4405 0.0569 0.0924
1 5 4 3.4381 0.0587 0.0944
6 3.4380 0.0595 0.0945
8 3.4379 0.0598 0.0949






0 5.0372 0.0819 0.0158
2 4.9523 0.0503 0.0193
1 0.2 4 4.9303 0.0530 0.0203
6 4.9393 0.0522 0.0205
8 4.9392 0.0523 0.0206






0 1.9481 1.1891 0.2289
2 1.9463 0.8866 0.2706
0.10.2 4 1.9453 0.9972 0.2932
6 1.9452 0.9853 0.2980
8 1.9452 0.9983 0.3018